### Games Interactive 2: Logical Impossibility

There are really two opposite ways to be stuck on a logic puzzle. The more usual way is to be unable to eliminate possibilities, so that the number of solutions under consideration is too large to simply iterate through. The other way is to eliminate all the possibilities. If you can do that, and the puzzle actually does have a solution, it means there’s an error in your reasoning somewhere, a variation that you’re forgetting about. But knowing that there’s an error doesn’t help much in finding it.

That’s the position I’m in with the last Battleships puzzle. There’s one four-long ship in every puzzle, and this puzzle has only one row or column that can hold it. Since the grid is 10×10, that means there are only seven positions this ship can go in. And I can prove every single one impossible.

There must be a mistake. That much is clear. But is the mistake mine or theirs? I actually think it’s probably mine in this instance. Battleships has a certain amount of error-detection built in. There are exactly 20 tiles worth of ships in every grid, so you can tell if there’s a mistake in one of the row or column numbers by adding them all up and seeing if you get 20. This would fail if there are two or more errors that cancel each other out perfectly, but how likely is that? So I think I’ll have to keep on looking for a solution here.

I can’t say the same for the last remaining Cross Math puzzle. Here, a similar summing technique proved that the puzzle is wrong. In these puzzles, you have to fill the numbers 1 through 9 in such a way to satisfy all six horizontal and vertical equations. Now, observe that the horizontal equations in this one have no multiplication or division. If they had nothing but addition, then the sum of all three rows would have to add up to the sum of all the numbers from 1 through 9, which is to say, 45. But some of the numbers are subtracted. The effect of subtracting a number instead of adding it is to subtract that number from the total sum twice: once for removing it as an addend, and once for the actual subtraction. So no matter what numbers have their signs flipped, the result will differ from 45 by an even number. The sum of all three rows therefore has to be odd. But this puzzle gives us rows that sum to 18.

Having thus convinced myself that at least one of the sums here was wrong, I told the game that I was done with the puzzle, and was pleased to be vindicated: in the game’s solution, the top row makes 8, not the 7 claimed. Proving a puzzle incorrect in this way is a sort of metapuzzle, and at least as satisfying as solving the puzzle itself.

How many of what kind of ship are there in the puzzle that you screenshotted?

It seems like I could make it a metapuzzle to try to figure that out by working out which constraints would support the deductions you’ve made, but if I want to bang my head against the wall that much I’ll just play Badland.

(Though this reminds me: Is it possible to use the fact that there must be a unique solution to work out the placement of the phials in that potion puzzle in Harry Potter and the Sorcerer’s Stone?)

The number of ships in Battleships is always the same: one four, two threes, three twos, and four ones. (In other words, for each type, the sum of the length and the quantity is five.)

If you’re asking because you intend to solve this one yourself, I should point out that most puzzles have a tile or two already filled in from the start. In this one, the only one filled in to start with was the endcap in the fourth column from the left.

Thanks! I looked up Battleships puzzles and figured out the ship distribution (it was hard for me to figure out because I didn’t have submarines in my game of Battleship). And the next question was going to be which tiles were filled in, so thanks for that.

Anyway, I’ve established to my satisfaction that the partial solution in the screenshot can’t work (if I’ve understood the rules correctly, since two ship can’t touch there’s no way to put another dot in the ninth row).

As for the Harry Potter problem, I actually did an analysis of it a number of years ago and came to the conclusion that, even with the knowledge that Hermione was able to solve the problem from the information she had, the reader does not. You can find my reasoning here: http://wurb.com/~carl/harrypotter

Ah thank you! I figured someone must have done it, and it stands to reason that it would have been you.